Calculating instantaneous acceleration

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Homework Help Overview

The problem involves calculating the instantaneous acceleration of a particle moving along the x-axis, with its position described by the equation x = 9.75 + 1.50t³, where t is in seconds. The original poster expresses confusion about how to derive acceleration from a position equation and mentions an attempt to find instantaneous velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to derive the position function to find velocity and then acceleration. Questions are raised about the original poster's calculation of velocity and understanding of derivatives.

Discussion Status

Some participants have provided guidance on deriving the position function to find velocity and acceleration. There is an ongoing exploration of the original poster's understanding of derivatives and their application to the problem. The discussion reflects a mix of attempts and clarifications without a clear consensus on the solution.

Contextual Notes

The original poster indicates a lack of confidence in their calculations and understanding, which may affect their ability to engage with the problem effectively. There is also a mention of language barriers impacting communication.

maxalador
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Homework Statement



The position of a particle moving along the x-axis is given in centimeters by x = 9.75 + 1.50t3, where t is in seconds

Calculate the instantaneous acceleration at 2.00 s.

Homework Equations


x = 9.75 + 1.50t3

I don't understand how i would solve for the acceleration using an equation for distance
i understand Vf=Vo+at and that the instantaneous velocity at this time is .217 m/s i had to teach myself how to do this so i am not sure i found the velocity correctly
 
Last edited:
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The way this works in PF is that you are supposed to make an attempt to solve the problem first, and show us what you did so far. Then, if necessary, we can try to get you pointed in the right direction.

Chet
 
Chestermiller said:
The way this works in PF is that you are supposed to make an attempt to solve the problem first, and show us what you did so far. Then, if necessary, we can try to get you pointed in the right direction.

Chet

Thanks for the info
 
You need to derive it. By t subject, do it twice. One derive tell you velocity, second tell you acceleration.
 
How did you arrive at v(2.00s) = 0.217 m/s? Are you familiar with what the derivative of position means?
 
Bandarigoda said:
You need to derive it. By t subject, do it twice. One derive tell you velocity, second tell you acceleration.

how would i derive it the second time
 
maxalador said:
how would i derive it the second time

You have a function for position with respect to time. Take the first time derivative. Show us what you get and what does this new function represent?
 
Clever-Name said:
How did you arrive at v(2.00s) = 0.217 m/s? Are you familiar with what the derivative of position means?

Did u ask it from me? I can't understand, sorry my bad english. Am i wrong about the derivation?
 
Bandarigoda said:
Did u ask it from me? I can't understand, sorry my bad english. Am i wrong about the derivation?

No, sorry, that was directed at maxalador.
 
  • #10
Clever-Name said:
No, sorry, that was directed at maxalador.

Oh okay. :)
 
  • #11
sorry guys it turns out that the reason i didnt understand was because i was doing it wrong. thanks for all your help though
 

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