Calculating Is and nVt for Silicon Diode, How?

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SUMMARY

The forum discussion centers on calculating the thermal voltage (nVt) and saturation current (Is) for a silicon diode, specifically the 1N4007-MIC. The user conducted an experiment using a DC power supply and a 1Kohm resistor to gather I-V characteristics data. To derive nVt, the user applies the equation V2-V1=2.3nVt log(I2/I1) using two points from the I-V curve. For Is, the equation I=Is e^(V/nVt) is utilized. The discussion confirms the user's methodology and suggests taking multiple readings for a more accurate nVt estimate.

PREREQUISITES
  • Understanding of diode characteristics and I-V curves
  • Familiarity with the 1N4007-MIC silicon diode specifications
  • Knowledge of logarithmic calculations in electronics
  • Basic circuit assembly skills, including series connections with resistors
NEXT STEPS
  • Research the thermal voltage (nVt) calculations for different diode types
  • Learn how to interpret V-I curves from diode datasheets
  • Explore methods for averaging multiple readings in experimental data analysis
  • Investigate alternative techniques for measuring Is and nVt in semiconductor devices
USEFUL FOR

Electronics students, lab instructors, and engineers involved in semiconductor research and diode applications will benefit from this discussion.

CDTOE
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Hello, everyone!

I was asked by my lab instructor for an Electronic course to conduct a diode experiment by which I can get the value of (nVt) and saturation current (Is) for that diode.

I did the experiment by connecting a DC power supply in series with a forward-biased silicon diode (1N4007-MIC), and a 1Kohm resistor. I took voltage reading across the diode starting from 10V DC supply, down to 1V. Now, I have the readings, plus I calculated the diode current (ID) for each -1V difference in DC supply. Also, I graphed a curve of I-V characteristics.

Well, I understand that to get the value of nVt and Is, I have to take two values on that curve, an upper value of VD(V2) on the horizontal axis corresponding to an upper value of ID(I2) on the vertical axis, and a lower value of VD(V1) corresponding to a lower value of ID(I1). I take these values and substitute in the equation:

V2-V1=2.3nVt log(I2/I1) --> From this, I can calculate the only unknown value which is nVt.I take the resulting value and substitute in the equation:

I=Is e^(V/nVt) --> From this, I can calculate the only unknown value which is Is.

So, my question is, is my understanding to how to get the two values correct? is there any shorter and easier way to get them?

Also, where can I find the the two values in the diode's datasheet? I looked up for it but didn't find any indication of it (this datasheet for example).

Thanks.
 
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Hi CDTOE! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

CDTOE said:
So, my question is, is my understanding to how to get the two values correct? is there any shorter and easier way to get them?
It looks fine. Take more than just 2 readings off the graph, and determine an average of your nVt estimates.

Also, where can I find the the two values in the diode's datasheet? I looked up for it but didn't find any indication of it (this datasheet for example).
You might have to deduce them from the typical V-I curve provided?
 
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