Calculating K Value for Fischer Esterification Homework

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Homework Statement


Hi.

In I'm doing a proposal for a lab and in it, it says that with an equilibrium constant value of 2 (K=2), the best yield would be about 59% of theoretical for a 1:1 ratio of reagents. I'm guessing it has to do with this equation, but I'm still sure how they calculated this value.

K = [ester][H2O] / [acid][alcohol]


Please show me how they got this value..


Thank you.
 
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I think it is an experimental value, it doesn't fit results of obvious approaches. Besides, I would say theoretical yield should take K (if known) into account.

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