Calculating Lattice Energy: LiF vs. CsF

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SUMMARY

The discussion focuses on calculating the lattice energy of lithium fluoride (LiF) and cesium fluoride (CsF). It establishes that the lattice energy is influenced by the distance between ion centers, denoted as 'r', and that larger ions result in a greater 'r' value. Consequently, LiF, with smaller ions compared to CsF, exhibits a more exothermic lattice energy due to its lower 'r' value, confirming the inverse relationship dictated by Coulomb's law.

PREREQUISITES
  • Coulomb's law for ionic interactions
  • Understanding of ionic compounds and their structures
  • Knowledge of ion sizes and their impact on lattice energy
  • Basic principles of thermodynamics related to exothermic reactions
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  • Study the application of Coulomb's law in lattice energy calculations
  • Research the factors affecting ionic radii and their implications
  • Explore the concept of lattice energy in other ionic compounds
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Chemistry students, materials scientists, and anyone interested in the thermodynamic properties of ionic compounds.

outofmines
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I'm having some problems with the calculations associated with this problem:

Which compound in each of the following pairs of ionic substances has the most exothermic lattice energy?

(a) LiF
CsF

I know I need to use Coulomb's law, but I don't know how to calculate r (the distance between the ion centers)

Any help is greatly appreciated. Thanks
 
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nevermind, I have found out that bigger ions have a bigger r value and thus via the inverse proportionality the higher lattice energy corresponds to the lower r value
 

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