Largest Lattice Energy: NaCl, CaO, Li2O, or CaCl2?

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Discussion Overview

The discussion revolves around determining which ionic compound among NaCl, CaO, Li2O, and CaCl2 has the largest lattice energy. Participants explore concepts related to ionic size, charge, and their effects on lattice energy, engaging in a homework-related inquiry.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant notes that smaller ionic size correlates with larger lattice energy, referencing trends in the periodic table.
  • Another participant questions the approach of comparing Na+ and Ca2+, suggesting that the number of protons must also be considered.
  • It is mentioned that the loss of electrons results in a smaller atomic radius, which could affect lattice energy calculations.
  • A participant highlights the importance of considering ionic charges, stating that lattice energy is directly proportional to the product of charges on ions and inversely proportional to the sum of ionic radii.

Areas of Agreement / Disagreement

Participants express varying views on how to approach the comparison of ionic sizes and charges, indicating that there is no consensus on the best method for determining which compound has the largest lattice energy.

Contextual Notes

Participants have not fully resolved the implications of ionic size and charge on lattice energy, and there are assumptions regarding the definitions of ionic radii and the effects of electron loss that remain unexamined.

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Homework Statement



Which one of the following ionic compounds has the largest lattice energy?

NaCl
CaO
Li2O
CaCl2



Homework Equations


Ionic/Atomic size
The smaller the ionic size, the larger the lattice energy.
Size increases from right to left, increases top to bottom of periodic table

The Attempt at a Solution


I've tried to compare the like ionic compounds, such as NaCl with CaCl2 but I can't seem to figure out which is bigger--Na+ or Ca2+

Am I approaching this incorrectly?
 
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Well if your losing electrons then the atomic size would what?
 
Loss of electrons means smaller atomic radius. But Na and Ca don't have the same number of protons so isn't there another way to have to look at it?
 
Well the loss of electrons makes the radius smaller. You know Na is one of the bigger elements size wise right? And the size decreases as you go across the periodic table. The protons don't attract the valence electrons as much as the core electrons b/c of shielding. Do you get it now?
 
are you considering charges?

L.E. is directly proportional to product of charges on ions but inversely proportional to sum of ionic radii.

hope it helps
 

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