Calculating Linear Expansion of Iron Rod for 2.51cm Ring Diameter

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SUMMARY

The discussion centers on calculating the temperature required for an iron rod with a diameter of 2.50 cm at 20.0° to fit into a ring with an inside diameter of 2.51 cm. The coefficient of linear expansion (alpha) is given as 1.0 x 10^-5. The formula for linear expansion, ΔL = (alpha)(L)(ΔT), is applicable, where L is the original length (or diameter in this case) and ΔT is the change in temperature. The diameter of the rod will expand similarly to its length, confirming that the same principles of thermal expansion apply.

PREREQUISITES
  • Understanding of linear expansion and thermal expansion concepts
  • Familiarity with the formula ΔL = (alpha)(L)(ΔT)
  • Basic knowledge of temperature measurement and conversion
  • Awareness of material properties, specifically for iron
NEXT STEPS
  • Calculate the required temperature change using the formula ΔL = (alpha)(L)(ΔT)
  • Research the thermal expansion properties of different materials
  • Explore applications of linear expansion in engineering and construction
  • Learn about temperature conversion methods for practical applications
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Students in physics or engineering, materials scientists, and professionals involved in manufacturing or construction who need to understand thermal expansion principles.

furielrage
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An iron rod has a diameter of 2.50cm at 20.0°. To what temperature must it be heated to fit into a ring with an inside diameter of 2.51cm. I'm given: alpha=1.0x10^-5

I'm not sure how to apply it to the △L=(alpha)(object length)△T
 
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Since the diameter is one dimensional quantity, L=2.50cm.
It seems a little bit strange but the diameter will expand just like a iron rod.
 

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