How Does Temperature Affect the Fit Between a Brass Ring and an Aluminum Rod?

  • Thread starter Thread starter whitehorsey
  • Start date Start date
  • Tags Tags
    Solids Thermal
Click For Summary
SUMMARY

The discussion centers on the thermal expansion of a brass ring and an aluminum rod, specifically how temperature affects their fit. A brass ring with a diameter of 10.00 cm at 20.0°C and an aluminum rod with a diameter of 10.01 cm at the same temperature can be separated by cooling them to a specific temperature, calculated using the linear expansion formula Δl = l0αΔT. The condition Lfrod = Lfring indicates that for separation, both must achieve the same diameter, which is critical for understanding the thermal expansion properties of both materials.

PREREQUISITES
  • Understanding of linear expansion of solids
  • Knowledge of coefficients of linear expansion for brass and aluminum
  • Familiarity with temperature measurement and conversion
  • Basic principles of thermal physics
NEXT STEPS
  • Research the coefficients of linear expansion for brass and aluminum
  • Learn how to apply the linear expansion formula Δl = l0αΔT in practical scenarios
  • Investigate the effects of temperature on the physical properties of metals
  • Explore methods for measuring thermal expansion in laboratory settings
USEFUL FOR

Students and professionals in materials science, mechanical engineering, and physics who are interested in the effects of temperature on material properties and thermal expansion.

whitehorsey
Messages
188
Reaction score
0
1.A brass ring of diameter 10.00 cm at 20.0°C is heated and slipped over an aluminum rod of diameter 10.01 cm at 20.0°C. Assuming the average coefficients of linear expansion are constant, (a) to what temperature must this combination be cooled to separate them? Is this attainable? (b) What if the aluminum rod were 10.02 cm in diameter?
Lfrod = Lfring


2. Linear expansion of solids Δl = l0αΔT



3. Shouldn't the temperature be heated instead to separate the ring and the rod because then it would expand? Also why is Lfrod = Lfring?
 
Physics news on Phys.org
If you heat the combined metals, both expand - what is the thermal expansion of aluminium, compared to the expansion of brass? Does heating (both together) work then?

What does Lfrod = Lfring mean?
To find the point where they get separable, both should have the same diameter.
 

Similar threads

How does thermal stress affect the length of a constrained rod?
  • · Replies 10 ·
Replies
10
Views
2K
Thermal Expansion Aluminium Problem
  • · Replies 1 ·
Replies
1
Views
3K
Finding Increase in Temperature for Two Rods
  • · Replies 3 ·
Replies
3
Views
2K
Thermal expansion of brass and iron rings
  • · Replies 2 ·
Replies
2
Views
4K
Heat and work. Fit ring over rod, remove ring from rod
  • · Replies 1 ·
Replies
1
Views
5K
How Cold to Separate a Heated Brass Ring from an Aluminum Rod?
  • · Replies 4 ·
Replies
4
Views
6K
Thermal coefficients of expansion
  • · Replies 5 ·
Replies
5
Views
2K
Calculating Thermal Expansion: Glass Rod Length, Diameter, and Volume Increase
  • · Replies 6 ·
Replies
6
Views
2K
Ring and Sphere Linear Expansion
  • · Replies 4 ·
Replies
4
Views
9K
Thermal Expansion of brass rod
  • · Replies 1 ·
Replies
1
Views
6K