Calculating Magnetic Field Inside a Toroidal Sample Using Ampere's Law

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The discussion focuses on calculating the magnetic field (B) inside a toroidal sample using Ampere's Law. Participants clarify that the magnetic field can be expressed in terms of the relative permeability (μr) by first determining the magnetic field strength (H). The relevant formulae include Ampere's Law in the form of ∮B·dl = μ0IN for N coils and the relationship H = B/μ, where μ = μ0μr. The conversation emphasizes the importance of correctly applying these equations to derive B in terms of μr.

PREREQUISITES
  • Understanding of Ampere's Law and its applications
  • Familiarity with magnetic field concepts, specifically in toroidal geometries
  • Knowledge of magnetic permeability, including relative permeability (μr) and permeability in vacuum (μ0)
  • Basic calculus for integrating magnetic field equations
NEXT STEPS
  • Study the derivation of magnetic field strength (H) in toroidal geometries
  • Learn about the implications of relative permeability (μr) in magnetic materials
  • Explore advanced applications of Ampere's Law in different geometries
  • Investigate the relationship between magnetic field (B) and magnetic field strength (H) in various contexts
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Physics students, electrical engineers, and anyone involved in magnetism and electromagnetic theory will benefit from this discussion.

Nylex
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Can someone help me with this please?

Consider a toroidal sample of magnetic material wound, uniformly, with coils of wire that carry a current I. If the total number of coils is N and the relative permeability of the material is μr, calculate the magnetic field B, inside the toroid at radius r.

The problem is expressing the magnetic field in terms of the relative permeability. In my notes, I have H = B/μ0μr, but I can't use that can I? I mean, I can't substitute B = μ0μrH into the Ampere's law integral, right?
 
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Of course u can,but viceversa,because Ampère's law contains H and u'll need to contain B.

It would be really helpful if that µ_{r} would be constant,as it would come out of the integral,just like I and µ_{0}.

Daniel.
 
you don't need integral for this problem... find H first, then B
H is easy...the formulas for H in a toroidal is...(hints: if your calculation takes you more than 10 seconds, that's mean you are going to a wrong way)
 
dextercioby said:
Of course u can,but viceversa,because Ampère's law contains H and u'll need to contain B.

It would be really helpful if that µ_{r} would be constant,as it would come out of the integral,just like I and µ_{0}.

Daniel.

I have only seen Ampere's law in the form of B . dl = µ0I (well, there's a form for simple media, H . dl = J . dS afaik, but I don't know what I'd use as dS :/). The µr is a constant in the question.

vincentchan said:
you don't need integral for this problem... find H first, then B
H is easy...the formulas for H in a toroidal is...(hints: if your calculation takes you more than 10 seconds, that's mean you are going to a wrong way)

I don't know what the formula for H in a toroid is! The version of Ampere's law with H (without displacement currents) and stuff is the one above.
 
The form of Ampére's law which u'll need is
\oint_{C} \vec{B}\cdot d\vec{l} =\mu_{0} I

which should give you the field created by 1 coil.For N,figure out what should b done.

Daniel.
 
dextercioby said:
The form of Ampére's law which u'll need is
\oint_{C} \vec{B}\cdot d\vec{l} =\mu_{0} I

which should give you the field created by 1 coil.For N,figure out what should b done.

Daniel.

Yeah, I know you just use \oint_{C} \vec{B}\cdot d\vec{l} =\mu_{0} IN for N coils. That wasn't the problem, it was expressing in terms of the relative permeability, which I'm still stuck on.

Thanks.
 
How about
\oint_{C} \vec{H}\cdot d\vec{l} = IN
and \vec{H}=\vec{B}/\mu
 
vincentchan said:
How about
\oint_{C} \vec{H}\cdot d\vec{l} = IN
and \vec{H}=\vec{B}/\mu

Which mu is that? Just \mu = \mu_{0} \mu_{r}?
 
Last edited:
yes... \mu = \mu_{0} \mu_{r}
That is the standard notaion... I used to write \mu instead of \mu_{0} \mu_{r}
 
  • #10
Of course one writes always µ when it comes to magnetic fields in matter,not in vacuum.Just because µ_{0} is an universal constant and µ_{r} is an adimensional constant,it's pointless to always write the product.

Daniel.
 

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