Calculating Magnetic Force on a Current-Carrying Wire

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SUMMARY

The discussion focuses on calculating the magnetic force on a current-carrying wire in a magnetic field of 8.4 x 10^-5 T, with the wire carrying a 7 A current over a length of 14.1 m. The initial calculation using the formula F = BIL sin(Ө) incorrectly assumed the angle between the current and the magnetic field was 40 degrees. The correct approach requires understanding that the angle is determined by the orientation of the magnetic field in relation to the current's direction, which is horizontal toward the east.

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fiyavan
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Hello guys

I have the following problem :

At a certain location, Earth has a magnetic field of 8.4 X 10^-5 T pointing 40 degree below the horizontal in a north-south plane. A 14.1m long straight wire carries a(n) 7 A current.
If the current is directed horizontally toward the east, what is the magnitude of the magnetic force on the wire?

I used the formula for the F = BIL sin Ө
so I get (8.4 X 10^-5 T)(7A)(14.1m) sin (40) = 0.0061775842N
for the magnetic force, but this is not the correct answer

Can anyone perhaps help me spot what am I doing wrong?
 
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Your error is thinking that the angle between the direction of the current and the direction of the magnetic field is 40 degrees. (40 degrees is the angle that the field makes with the horizontal, but in a north-south plane.)
 
hmm

reading the problem again, it does seem like that's my problem, but I am still not quite understanding the wording of the problem, can you explain it to me please?
 
Here's how I visualize it: Take east to be the +x direction; north to be the +y direction. Below the horizontal means in the -z direction. The magnetic field vector is in the y-z plane. (What's the angle between the x-axis and the y-z plane?)
 
wouldnt it still be 10 degrees?
 

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