Calculating Magnetic Moment of Hydrogen Atom

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Homework Help Overview

The discussion revolves around calculating the magnetic moment of a hydrogen atom, given specific parameters such as the electron's velocity and orbital radius. The subject area includes concepts from electromagnetism and atomic physics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between current, charge, and velocity to derive the magnetic moment. There are attempts to clarify the variables involved, such as the number of free electrons and the correct formulation of the equations used.

Discussion Status

Several participants provide feedback on the equations being used, with some suggesting re-evaluations of the units and formulations. There is an ongoing exploration of the correct approach to calculating the magnetic moment, with hints and corrections being shared among participants.

Contextual Notes

There are indications of typos and misunderstandings regarding the variables and equations, which participants are actively addressing. The discussion reflects a collaborative effort to verify calculations and clarify concepts without reaching a definitive conclusion.

iontail
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Homework Statement



find the magnetic moment of a hydrogen atom given that the election moves at 0.10c around the nucleus and the radius is 0.5*10^-5 m

Homework Equations



n/a

The Attempt at a Solution



this is what i did.

I = nev
=ev (I = current e= charge of electron, v = velocity)

m = IA (A = area)

my result is 12 A m^2.

The result looks too big...am I doing something wrong. can you please verify that my answer is right.
 
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iontail said:
I = nev
=ev (I = current e= charge of electron, v = velocity)
What's n?

Hint: Find the current by figuring out long it takes for the electron to orbit the nucleus.
 
Your approach is correct, you may want to check your units.

e = 1.6*10^-19 coulomb
v = 3*10^7 m/s
r = 0.5*10^-5 m

I = q v
m = I pi r^2

I get:

I = 4.8*10^-12
m = 3.77*10^-22
 
jpreed said:
I = q v
You might want to rethink that equation.
 
Doc Al said:
You might want to rethink that equation.


hi sorry about that i made a typo.
n=number of free electron

and I = nev/(r*pi*r) (r= radius of atom)

the answer i got before is still correct. I just made a typo while putting the detials in the computer.

I am just suprised that the magnetic moment for an atom is so high. CAn you please verify the answer. or tell me if i have made any other mistake.
 
iontail said:
hi sorry about that i made a typo.
n=number of free electron
OK, so n = 1.

and I = nev/(r*pi*r) (r= radius of atom)
That doesn't look right. (Check the units.)
 
Doc Al said:
OK, so n = 1.


That doesn't look right. (Check the units.)

I = ev/2*pi*r

it should be right now.
 
iontail said:
I = ev/2*pi*r

it should be right now.
Now you've got it.
 
Doc Al said:
You might want to rethink that equation.

Oops, I forgot to normalize by the distance. You are right.

It should be

I = q v / (2 pi r)
 
  • #10
jpreed said:
Oops, I forgot to normalize by the distance. You are right.

It should be


I = q v / (2 pi r)


thabk you all for you help...
 

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