Calculating magnetomotive force in a transformer

  • Thread starter Thread starter bitrex
  • Start date Start date
  • Tags Tags
    Force Transformer
Click For Summary
SUMMARY

The calculation of magnetomotive force (MMF) in a transformer can be performed using the relationship between primary inductance, current, and the magnetic field. Specifically, the formula (1/2) L I² = (1/2) ∫ B H dV is utilized, where L represents inductance, I is the magnetizing current, B is the magnetic flux density in Tesla, H is the magnetizing force in amp-turns per meter, and V is the volume of the magnetic material. The relative permeability (u) and the permeability of free space (u0 = 4π x 10^-7 H/m) are critical in determining the B field. This approach allows for accurate calculations of MMF when the output of the transformer is open-circuited.

PREREQUISITES
  • Understanding of transformer principles and operation
  • Familiarity with inductance and its role in magnetic circuits
  • Knowledge of magnetic field concepts, including B and H fields
  • Basic calculus for evaluating integrals over volume
NEXT STEPS
  • Study the relationship between inductance and magnetizing current in transformers
  • Learn about the calculation of magnetic fields in ferromagnetic materials
  • Explore the concept of relative permeability and its impact on transformer design
  • Investigate the effects of open-circuit conditions on transformer performance
USEFUL FOR

Electrical engineers, transformer designers, and students studying electromagnetic theory will benefit from this discussion, particularly those focused on calculating magnetomotive force and understanding transformer behavior under open-circuit conditions.

bitrex
Messages
190
Reaction score
0
If I have a transformer with a known primary inductance and number of turns, and the output is open circuited, how would I go about calculating the magnetomotive force created by the magnetizing current?
 
Engineering news on Phys.org
You can determine the B field in the transformer by equating the engineering and physics version of the stored energy:
(1/2) L I2 = (1/2) ∫ B H dV

where L = inductance, I = current, B = u u0 H, B=Tesla, H=amp-turns per meter, V = integral over volume of iron, u = relative permeability, u0 = 4 pi x 10-7 Henrys per meter..

∂ ∫ ∏ ∑
 

Similar threads

Replies
10
Views
3K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
770
  • · Replies 8 ·
Replies
8
Views
2K
Replies
5
Views
3K