Calculating Mass and Height Changes in a Hydraulic Lift

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SUMMARY

The discussion focuses on calculating mass and height changes in a hydraulic lift system with two pistons of cross-sectional areas 5 cm² and 650 cm², filled with oil of density 720 kg/m³. To support a car weighing 1400 kg, a mass of 10.77 kg must be placed on the smaller piston. When an additional person weighing 80 kg enters the car, the equilibrium height difference in the fluid levels is determined to be 1.7 cm. The user is seeking guidance on calculating the height drop of the car when the person enters.

PREREQUISITES
  • Understanding of Pascal's principle in hydraulics
  • Knowledge of pressure calculations (P = F/A)
  • Familiarity with fluid density and its role in buoyancy
  • Basic algebra for solving equations related to mass and height changes
NEXT STEPS
  • Study Pascal's principle and its applications in hydraulic systems
  • Learn about pressure calculations in fluid mechanics
  • Research the relationship between mass, density, and volume in fluids
  • Explore the concept of equilibrium in hydraulic lifts and related calculations
USEFUL FOR

Engineering students, mechanical engineers, and anyone involved in designing or analyzing hydraulic systems will benefit from this discussion.

mattmannmf
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A hydraulic lift has two connected pistons with cross-sectional areas 5 cm2 and 650 cm2. It is filled with oil of density 720 kg/m3.

a) What mass must be placed on the small piston to support a car of mass 1400 kg at equal fluid levels?

10.77 OK

b) With the lift in balance with equal fluid levels, a person of mass 80 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons?


c) How much did the height of the car drop when the person got in the car?

Now what i started off with was that pressure= mg/A (1480*9.8/ 650) and that equals density(g)(h)...so i got height change to be .003...but that's wrong
 
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so i figured out B..its 1.7

I just have no idea where to start for C
 

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