How Does a Hydraulic Lift Work with Different Piston Sizes and Weights?

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SUMMARY

The discussion focuses on the mechanics of a hydraulic lift involving two pistons with cross-sectional areas of 15 cm² and 460 cm², filled with oil of density 560 kg/m³. To support a car weighing 1100 kg, a mass of 35.86 kg must be placed on the smaller piston. When a person weighing 70 kg enters the car, the equilibrium height difference in the fluid levels between the pistons is calculated to be 2.72 m. The challenge lies in determining how much the car drops when the person enters, requiring an understanding of fluid mechanics and the distribution of height changes between the pistons.

PREREQUISITES
  • Understanding of Pascal's Principle in hydraulics
  • Basic knowledge of fluid density and its effects on pressure
  • Familiarity with the concept of equilibrium in hydraulic systems
  • Ability to perform calculations involving area, mass, and height in fluid mechanics
NEXT STEPS
  • Study Pascal's Principle and its applications in hydraulic systems
  • Learn about fluid density and pressure calculations in hydraulics
  • Explore the relationship between piston sizes and weight distribution in hydraulic lifts
  • Investigate the effects of additional loads on hydraulic lift equilibrium
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Students studying physics, engineers working with hydraulic systems, and anyone interested in the practical applications of fluid mechanics in lifting devices.

mrnastytime
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Homework Statement


A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 460 cm2. It is filled with oil of density 560 kg/m3.


Homework Equations


a)What mass must be placed on the small piston to support a car of mass 1100 kg at equal fluid levels?
A:35.86 kg
b)With the lift in balance with equal fluid levels, a person of mass 70 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons?
A:2.72 m
c) How much did the height of the car drop when the person got in the car?


The Attempt at a Solution


Take the difference in height when its the only the car, then find difference in height of car + guy. Subtract those two. But its not working.
 
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It seems to me that, when the guy got in the car, the car went down but the 38.5 kg weight on the other piston went up. So you have to share out that 2.72 metres between how much the car went down and how much the other piston went up.
 

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