- #1

bricker9236

- 10

- 0

## Homework Statement

A hydraulic lift has two connected pistons with cross-sectional areas 25 cm2 and 250 cm2. It is filled with oil of density 510 kg/m3.

a) What mass must be placed on the small piston to support a car of mass 1200 kg at equal fluid levels? I got this answer - 120 kg

b) With the lift in balance with equal fluid levels, a person of mass 90 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons?

i got this answer 7.0588m

c) How much did the height of the car drop when the person got in the car?

HELP: The fluid is incompressible, so volume is conserved.

HELP: Remember, one side will go up and one side will go down. The difference you calculated in part (b) was the sum of those two changes.

C is the part that i am very confused on. I thought i was doing it correct and apparently not.

## Homework Equations

h1+h2 = 7.0588

I thought this was the equation i used to figure out part C but i am just lost on it.

## The Attempt at a Solution

above.