Calculating Mass Density of a Steel Sphere | Help Needed!

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SUMMARY

The discussion centers on calculating the mass density of a steel sphere with a mass of 8.4 grams and a volume of 1060 cm³. The initial calculation yielded a density of 0.0079 g/cm³, which is incorrect due to a misinterpretation of the diameter measurement. The correct diameter is likely 12.65 mm, not cm, leading to a recalculated density of 7.9 g/cm³, aligning with the accepted value for steel. The percent error calculation was also flawed, resulting in a misleading error of nearly 100%.

PREREQUISITES
  • Understanding of mass density calculations
  • Familiarity with volume formulas for spheres, specifically V = (4/3)πR³
  • Knowledge of unit conversions between grams and kilograms, and cm³ to m³
  • Experience with using a micrometer for measuring small diameters
NEXT STEPS
  • Recalculate mass density using the correct diameter of 12.65 mm
  • Learn about common measurement errors in laboratory settings
  • Study the principles of percent error calculation in scientific experiments
  • Explore the properties of steel and its standard density values
USEFUL FOR

Students in physics or engineering courses, laboratory technicians, and anyone involved in material science or density measurements will benefit from this discussion.

derivethis
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Hi all! This is my first post here. I have a question regarding how to calculate the mass density of a steel sphere. Any help is much appreciated!

Homework Statement


The mass of the sphere is equal to 8.4 grams. The volume of the sphere is equal to 1060 cm^3.


Homework Equations


The mass was found during our lab experiment. The volume was calculated from the equation: V = (4/3) pi R^3. The diameter of the sphere was 12.65 cm. Therefore, I calculated the volume as follows: (4/3) pi (12.65/2)^3 = 1060 cm^3.


The Attempt at a Solution


Mass density is equal to mass/volume; therefore it should be 8.4g/1060cm^3 = 0.0079gm/cm^3. However, I'm also supposed to calculate the percent error for my lab report, and the "true" value for the mass density of steel is given as 7.9 gm/cm^3. Percent error is equal to (|Accepted - Measured|)/Accepted * 100, which, in this case, would be (|7.9 - 0.0079|)/7.9 * 100 = 99.9%. This gives me a percent error of almost 100%! What am I doing wrong in my calculations? Please help! Thank you!
 
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Are you sure you have your units right?

1 gram = 10^-3 kg. And 1 cm^3 = 10^-6 m^3.

so 1 g/cm^3 = 10^-3 / 10^-6 kg/m^3 = 10^3 kg/cm

so your 0.0079 g/cm^3 = 7.9 kg/m^3.
 
Your volume is about 1000 cm3, which is 1 liter. Does that sound right?
 
Thank you for your replies!

l'Hôpital: I think that I'm supposed to keep the units in grams/cm^3. I think my lab group and I must have made some sort of error in lab, which, of course, I can't correct now. We had to use a micrometer to determine the diameter of the steel sphere, and I just now realized that there's no way that the diameter of the sphere was 12.65 centimeters since the sphere was tiny and 1 inch = 2.54 cm. Hmm ... I wonder if it should be 12.65 mm instead. I believe that when we used the micrometer, we had to take it out to the number 10 mark in order for the sphere to fit inside. Does anyone know what this means? Thank you!
 
derivethis said:
Thank you for your replies!

l'Hôpital: I think that I'm supposed to keep the units in grams/cm^3. I think my lab group and I must have made some sort of error in lab, which, of course, I can't correct now. We had to use a micrometer to determine the diameter of the steel sphere, and I just now realized that there's no way that the diameter of the sphere was 12.65 centimeters since the sphere was tiny and 1 inch = 2.54 cm. Hmm ... I wonder if it should be 12.65 mm instead. I believe that when we used the micrometer, we had to take it out to the number 10 mark in order for the sphere to fit inside. Does anyone know what this means? Thank you!
That doesn't really tell us much unless we would have access to the same kind of micrometer you used.

There's a decent chance that your measurement of the diameter was off by a factor of 10 - that's a relatively common mistake to make. So it might have been 12.65mm. Based on your memory of what the sphere looked like, does 12.65mm seem like a reasonable value for its diameter? If so, try recalculating the density using that diameter and see what you get.
 

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