Density: Cube of Aluminum to Copper Sphere

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Homework Help Overview

The problem involves finding the diameter of a copper sphere that has the same mass as a cube of aluminum, with given densities for both materials. The original poster presents calculations for mass, volume, and radius but indicates a discrepancy with the expected result.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the mass of the aluminum cube and then uses that to find the volume and radius of the copper sphere. Some participants question the calculations, particularly the radius derived from the volume equation.

Discussion Status

Participants are actively engaging with the calculations presented. There is recognition of a potential error in the calculation of the radius, and the original poster acknowledges a mistake in the approach. The discussion is ongoing, with attempts to clarify the mathematical reasoning involved.

Contextual Notes

The original poster expresses concern about following the forum's posting format and seeks feedback on their approach. There is an indication of a misunderstanding in the calculation process that may have led to the incorrect result.

JustinDaniels
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Homework Statement


What is the diameter of a copper sphere that has the same mass as a 9.00 cm× 9.00 cm× 9.00 cm cube of aluminum?

Density of Aluminum = P(al) = 2.70g/cm3
Density of Copper = P(cu) = 8.96 g/cm3

Volume of Aluminum Cube = Vcube = 729 cm3

Homework Equations


Volume of a Sphere = 4/3pi(r3) - Note: We are solving for 2r (i.e. the diameter).
Density = Mass/Volume

The Attempt at a Solution


1) Find the mass of the aluminum cube.
Density = Mass/Volume - substitute in known values
2.70g/cm3 = mass/729cm3
Mass = 1968.3 grams

2) Find the volume of the sphere.
Density = Mass/Volume
8.96 g/cm3 = 1968.3g/Volume
Volume = 219.676 cm3

3) Find the radius of the sphere.
Volume of a Sphere = 4/3pi(r3) - substitute in known values
219.676 = 4/3pi(r3)
Radius = 52.4438 cm

Diameter = Radius * 2 = 104.8877 cm

Everything looks pretty spot on to me; however, my online homework says this is incorrect. Any help would be greatly appreciated.

Thanks guys,
Justin Daniels.

P.S. This is my first post. Please let me know if I've failed to follow the format for posting questions, so I can correct this moving forward.
 
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Edit: I forgot to take the cubic root of the radius when solving in step 3. Sorry for the pointless thread, and thank you guys anyway!
 
JustinDaniels said:
219.676 = 4/3pi(r3)
Radius = 52.4438 cm
Your equation cannot possibly produce a radius that large. Check the calculation.
 
JustinDaniels said:
Edit: I forgot to take the cubic root of the radius when solving in step 3. Sorry for the pointless thread, and thank you guys anyway!
We crossed in the post.
 

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