Density: Cube of Aluminum to Copper Sphere

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SUMMARY

The discussion centers on calculating the diameter of a copper sphere that matches the mass of a 9.00 cm cube of aluminum. The density of aluminum is 2.70 g/cm³, and the density of copper is 8.96 g/cm³. The mass of the aluminum cube is determined to be 1968.3 grams, leading to a calculated volume of the copper sphere of 219.676 cm³. The initial calculation of the radius was incorrect due to a failure to take the cubic root, resulting in an erroneous diameter of 104.8877 cm.

PREREQUISITES
  • Understanding of density and its formula (Density = Mass/Volume)
  • Knowledge of volume calculations for geometric shapes, specifically spheres
  • Familiarity with algebraic manipulation and solving equations
  • Basic understanding of cubic roots and their application in volume calculations
NEXT STEPS
  • Review the formula for the volume of a sphere: V = 4/3πr³
  • Learn how to calculate mass from density and volume using the formula: Mass = Density × Volume
  • Study the concept of cubic roots and their significance in geometry
  • Practice problems involving density and volume calculations for various shapes
USEFUL FOR

Students in physics or chemistry courses, educators teaching density and volume concepts, and anyone seeking to improve their problem-solving skills in geometry and algebra.

JustinDaniels
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Homework Statement


What is the diameter of a copper sphere that has the same mass as a 9.00 cm× 9.00 cm× 9.00 cm cube of aluminum?

Density of Aluminum = P(al) = 2.70g/cm3
Density of Copper = P(cu) = 8.96 g/cm3

Volume of Aluminum Cube = Vcube = 729 cm3

Homework Equations


Volume of a Sphere = 4/3pi(r3) - Note: We are solving for 2r (i.e. the diameter).
Density = Mass/Volume

The Attempt at a Solution


1) Find the mass of the aluminum cube.
Density = Mass/Volume - substitute in known values
2.70g/cm3 = mass/729cm3
Mass = 1968.3 grams

2) Find the volume of the sphere.
Density = Mass/Volume
8.96 g/cm3 = 1968.3g/Volume
Volume = 219.676 cm3

3) Find the radius of the sphere.
Volume of a Sphere = 4/3pi(r3) - substitute in known values
219.676 = 4/3pi(r3)
Radius = 52.4438 cm

Diameter = Radius * 2 = 104.8877 cm

Everything looks pretty spot on to me; however, my online homework says this is incorrect. Any help would be greatly appreciated.

Thanks guys,
Justin Daniels.

P.S. This is my first post. Please let me know if I've failed to follow the format for posting questions, so I can correct this moving forward.
 
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Edit: I forgot to take the cubic root of the radius when solving in step 3. Sorry for the pointless thread, and thank you guys anyway!
 
JustinDaniels said:
219.676 = 4/3pi(r3)
Radius = 52.4438 cm
Your equation cannot possibly produce a radius that large. Check the calculation.
 
JustinDaniels said:
Edit: I forgot to take the cubic root of the radius when solving in step 3. Sorry for the pointless thread, and thank you guys anyway!
We crossed in the post.
 

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