Calculating Mass of Liquid in Vat

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SUMMARY

The discussion focuses on calculating the mass of liquid in a vat with a diameter of 1.60 m and a depth of 2.30 m, where the pressure at the bottom is 1.20 atm. The initial calculations incorrectly applied the formula for mass, leading to an erroneous result of 399 kg. The correct approach involves using the relationship between pressure, area, and weight, emphasizing the need to rearrange the formula to isolate mass. The correct mass calculation should account for the pressure conversion from atm to kPa and the gravitational force.

PREREQUISITES
  • Understanding of fluid pressure and its units (e.g., atm, kPa).
  • Knowledge of the formula for area of a circle (A = πr²).
  • Familiarity with the relationship between mass, weight, and gravitational acceleration (F = mg).
  • Ability to convert pressure units and apply them in calculations.
NEXT STEPS
  • Learn how to convert pressure from atm to kPa accurately.
  • Study the principles of hydrostatic pressure in fluids.
  • Explore the derivation and application of the mass-weight relationship in physics.
  • Practice problems involving the calculation of mass from pressure and area in various contexts.
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Students studying physics, particularly those focusing on fluid mechanics, as well as educators looking for examples of mass calculations in real-world applications.

benedict9999
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Homework Statement
A 1.60 m-diameter vat of liquid is 2.30 m deep. The pressure at the bottom of the vat is 1.20 atm. What is the mass of the liquid in the vat in Kg?


The attempt at a solution
A= pi*r^2 = pi (0.8)^2 = 2.01 m^2

2.01m^2 x 20.260 kPa = 40.7226

40.7226 x 9.8 = 399kg

and i got it wrong :(
 
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benedict9999 said:
The attempt at a solution
A= pi*r^2 = pi (0.8)^2 = 2.01 m^2

2.01m^2 x 20.260 kPa = 40.7226

40.7226 x 9.8 = 399kg

and i got it wrong :(

You're very close. What is the equation relating mass and weight?

p.s. Welcome to Physics Forums.
 
Hi benedict9999! :smile:
benedict9999 said:
A 1.60 m-diameter vat of liquid is 2.30 m deep. The pressure at the bottom of the vat is 1.20 atm. What is the mass of the liquid in the vat in Kg?
…
40.7226 x 9.8 = 399kg

and i got it wrong :(

Force = mass times acceleration,

so why is your g on the left? :wink:
 

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