- #1
CeilingFan
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Homework Statement
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Hi, not sure if I posted this in the correct section... I have a solution, but am unsure if I am correct in going about it. The answer is not given, so I am having trouble figuring if I'm right or not.
Anyway, the question goes like this.
Saturated water mixture initially in a piston-cylinder device with a stopper.
Initial state: Volume, V1 = 0.00078539 m^3
Quality, x = 0.85
Pressure, P1 = 125 kPa
Heat is then introduced, after which the piston hits the stopper. The heating is continued until the pressure reaches 200 kPa.
Final state: Volume, V2 = 2Vi = 0.00157079
Pressure, P2 = 200 kPa
a) Find the initial temperature and mass of the liquid.
b) How is the final state, and what is its temperature?
The Attempt at a Solution
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a) I used the provided saturated water table, to find Tsat for P = 125 kPa, and got 105.97C.
For the mass of the liquid, I used x = (v1 - vf) / (vg - vf), where required values are retrieved from the table.
which gave v1 = 1.1689 m^3/kg
Mass of entire mixture, mt = V1/v1 = 0.00067191 kg
x = (mt - mL) / mt
mL = 0.00010078 kg
b) For the final state, I checked the saturated table for P = 200 kPa and found that the specific volume of the substance in question is more than that of saturated vapor at 200 kPa, so using that logic I deduced the final state to be superheated vapor.
v2 = V2 / mt
The temperature is then interpolated from the superheated vapor table at 200 kPa using the specific volume.
It was about 740 degrees celcius.
** Additional thought
Also, if the question required me to think about the state just as the piston hits the stopper, do I use P = 125 kPa, to find the specific volume and compare it with that in the saturated water table? So if v > v of gas --> superheated vapor?