Calculating Mass of Liquid in Vat

[benedict9999]

Homework Statement
A 1.60 m-diameter vat of liquid is 2.30 m deep. The pressure at the bottom of the vat is 1.20 atm. What is the mass of the liquid in the vat in Kg?


The attempt at a solution
A= pi*r^2 = pi (0.8)^2 = 2.01 m^2

2.01m^2 x 20.260 kPa = 40.7226

40.7226 x 9.8 = 399kg

and i got it wrong :(

 

[Redbelly98]

The attempt at a solution
A= pi*r^2 = pi (0.8)^2 = 2.01 m^2

2.01m^2 x 20.260 kPa = 40.7226

40.7226 x 9.8 = 399kg

and i got it wrong :(

You're very close. What is the equation relating mass and weight?

p.s. Welcome to Physics Forums.

 

[tiny-tim]

Hi benedict9999!

A 1.60 m-diameter vat of liquid is 2.30 m deep. The pressure at the bottom of the vat is 1.20 atm. What is the mass of the liquid in the vat in Kg?
…
40.7226 x 9.8 = 399kg

and i got it wrong :(

Force = mass times acceleration,

so why is your g on the left?