The minimum work required to push an 800 kg car up a 930 m incline at a 9.0° angle can be calculated using the change in gravitational potential energy. The formula W = Fdcos(θ) is applicable, where F represents the gravitational force component along the incline. To find F, calculate the height increase using the sine of the incline angle and multiply it by the mass and gravitational acceleration (9.81 m/s²). The correct approach simplifies to determining the potential energy change rather than directly calculating force.
PREREQUISITESStudents studying physics, engineers working on mechanical systems, and anyone interested in understanding work and energy concepts in inclined planes.
)There are a couple of ways to approach this. One way is to calculate the component of force (gravity) along (ie. parallel to) the 9.0^\circ inclined surface and multiply that force by the distance (930 m). The simpler way would be to determine the height increase over that 930 m and the resulting change in gravitational potential energy of the car. The work is equal to the change in gravitational potential energy.cmed07 said:
tiny-tim said:Hi cmed07! Welcome to PF!
(have a theta: θ and a degree: º
First, what is the minimum possible value of F?
cmed07 said:
