1. The problem statement, all variables and given/known data Crash Test Craig drives his 800kg car up a 100m ramp that is at an angle of 35 degrees above the horizontal. The car exerts a forward force of 12000N and the force of friction between the ramp and the car is 20N. He is trying to jump over a series of spinning helicopter blades that are each 8m across to reach another ramp down on the other side How many helicopter blades can he safely jump over? Variables: mass of car= 800 kg distance or length of ramp= 100m angle= 35 degrees Applied(?) force= 12000N Force of friction= 20N Normal force= 9.8 m/s^2 * 800 kg = 7,840N Force of gravity= 9.8 m/s^2 * 800kg = 7,840N 2. Relevant equations Vf^2=Vi^2 + 2ad F=ma There could be a variety of kinematics equations to use. 3. The attempt at a solution So, I thought since the car was exerting 12000N, that we could find the acceleration of the car using F=ma. I thought 12000N= 800kg*a and got a to be 15m/s^2. Then, assuming that initial velocity is 0 m/s, I solved for the final velocity using Vf^2= Vi^2 + 2ad. Vf^2= (0m/s)^2 + 2(15m/s^2)(100m). Vf= 54.77 m/s which is the launch velocity of the car as if leaves the ramp. I know I need to find the distance the car travels in the air and divide that by 8 to get the number of helicopter blades, but I am confused by what to do next. Would final velocity be 0 m/s? Is acceleration 9.8 m/s^2? Is it now a vector problem? Do I use the force in any way?