Calculating Min Work for 800kg Car on 9.0° Incline

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Homework Help Overview

The problem involves calculating the minimum work required to push an 800 kg car up a 930 m incline at an angle of 9.0°. The subject area pertains to mechanics, specifically work and energy concepts.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for work and the force required to move the car. There are mentions of calculating the gravitational force component along the incline and considering the change in gravitational potential energy as an alternative approach. Questions arise regarding the minimum possible value of force and the calculations leading to perceived errors.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some guidance has been offered regarding the calculation of force and potential energy, but no consensus has been reached on the correct method or interpretation of the problem.

Contextual Notes

Participants note that the information provided may be limited, and there is uncertainty regarding the calculations leading to the results. The original poster expresses confusion about the values obtained from the formulas used.

cmed07
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I have been trying this problem multiple times but it still says I'm wrong:

What is the minimum work needed to push a 800 kg car 930 m up along a 9.0^\circ incline?

i'm using the formula:
W= Fdcos(theta)
F= mg

what am i doing wrong?
 
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Welcome to PF!

Hi cmed07! Welcome to PF! :smile:

(have a theta: θ and a degree: º :wink:)

First, what is the minimum possible value of F?
 
cmed07 said:
I have been trying this problem multiple times but it still says I'm wrong:

What is the minimum work needed to push a 800 kg car 930 m up along a 9.0^\circ incline?

i'm using the formula:
W= Fdcos(theta)
F= mg

what am i doing wrong?
There are a couple of ways to approach this. One way is to calculate the component of force (gravity) along (ie. parallel to) the 9.0^\circ inclined surface and multiply that force by the distance (930 m). The simpler way would be to determine the height increase over that 930 m and the resulting change in gravitational potential energy of the car. The work is equal to the change in gravitational potential energy.

AM
 


tiny-tim said:
Hi cmed07! Welcome to PF! :smile:

(have a theta: θ and a degree: º :wink:)

First, what is the minimum possible value of F?


That's all the information that was given to me... I know I'm supposed to find force by multiplying the mass and gravity...but i think the number I'm getting after i put it into the work formula is too big...
 
cmed07 said:
That's all the information that was given to me...

D'oh! :rolleyes:

On the information that was given to you, what is the minimum possible value of F? :smile:
 

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