Calculating Minimum Force for Turning a Barrel over a Step

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arkofnoah said:
OH! actually i just realized we don't need to do all that.

F x 0.3 = 1500 x 0.4

That's it (the sides of the triangle I've drawn is found using pythagoras' theorem). Sorry for complicating the matter :-p

where does 0.4 comes from ??
 
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why do all these? from the centre of the barrel to the edge, its still the radius that is concerned , which is 0.5. is there a need to use pythagoras theorem ??
 
you need to find the perpendicular distance from either of the forces to the fulcrum (i.e. the edge). Look at my diagram again the 0.4 is one of the sides of the triangle I've found using pythagoras' theorem. This is the simplest method.