Calculating Minimum Force for Turning a Barrel over a Step

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Homework Help Overview

The problem involves calculating the minimum horizontal force required to push a barrel over a step. The context includes principles of moments and torque, as well as geometric considerations related to the barrel's dimensions and the step's height.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the principle of moments and torque calculations, questioning the height at which the force is applied and the location of the pivot point. There are attempts to clarify the geometry involved, including the distances relevant to the barrel and the step.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem setup. Some have offered insights into the geometric relationships and the need for trigonometric considerations, while others express uncertainty about the calculations and seek alternative methods.

Contextual Notes

There are mentions of potential confusion regarding the dimensions of the barrel and the step, as well as the application of trigonometry versus geometry in solving the problem. Participants note that they have not all learned trigonometry, which may affect their ability to engage with certain suggested methods.

  • #31
arkofnoah said:
OH! actually i just realized we don't need to do all that.

F x 0.3 = 1500 x 0.4

That's it (the sides of the triangle I've drawn is found using pythagoras' theorem). Sorry for complicating the matter :-p

where does 0.4 comes from ??
 
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  • #32
why do all these? from the centre of the barrel to the edge, its still the radius that is concerned , which is 0.5. is there a need to use pythagoras theorem ??
 
  • #33
you need to find the perpendicular distance from either of the forces to the fulcrum (i.e. the edge). Look at my diagram again the 0.4 is one of the sides of the triangle I've found using pythagoras' theorem. This is the simplest method.
 

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