Calculating Molarity of NaOH in a Titration/pH Problem

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SUMMARY

The discussion focuses on calculating the molarity of sodium hydroxide (NaOH) used in a titration with cyclohexylaminoethanesulfonic acid. Given that 22.63 mL of NaOH was added to 1.226 g of the acid dissolved in 41.37 mL of water, and the resulting pH was measured at 9.24, participants emphasized the importance of determining the pKa value from a reference table to facilitate the calculation. The molarity of NaOH can be derived using the formula M = moles of solute/volume of solution in liters.

PREREQUISITES
  • Understanding of acid-base titration concepts
  • Familiarity with pH calculations and pKa values
  • Knowledge of molarity calculations
  • Basic chemistry knowledge regarding cyclohexylaminoethanesulfonic acid and NaOH
NEXT STEPS
  • Calculate the moles of cyclohexylaminoethanesulfonic acid using its molar mass (207.29 g/mol)
  • Research how to find pKa values from chemical reference tables
  • Learn about the Henderson-Hasselbalch equation for pH calculations
  • Practice titration calculations with different acids and bases
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in teaching acid-base titration techniques and calculations.

emc92
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When 22.63 mL of aqueous NaOH was added to 1.226 g of cyclohexylaminoethanesulfonic acid (FM 207.29, structure in the table) dissolved in 41.37 mL of water, the pH was 9.24. Calculate the molarity of the NaOH.

How do I start this calculation?
 
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Most likely finding pKa in the table.

Please don't ignore the template, it is there to help you organize your thoughts, and to help us point you in the right direction.
 

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