Calculating Moles of NaCN from Gram Formula Weight

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SUMMARY

The discussion centers on calculating the number of moles from the gram formula weight of sodium cyanide (NaCN). The correct interpretation is that 0.01 gram formula weight of NaCN directly equates to 0.01 moles, as 1 gram formula weight corresponds to 1 mole of the substance. The confusion arises from the misconception that gram formula weight should be divided by the molar mass (49 g/mol for NaCN) to find moles, which is incorrect in this context. The term "gram formula weight" is clarified as synonymous with "mole" for this calculation.

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  • Understanding of mole concept in chemistry
  • Familiarity with gram formula weight and its implications
  • Basic knowledge of sodium cyanide (NaCN) and its properties
  • Ability to perform simple unit conversions in chemistry
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  • Study the mole concept and its applications in chemical calculations
  • Learn about gram formula weight and how it relates to moles
  • Explore the properties and uses of sodium cyanide (NaCN) in chemistry
  • Review common misconceptions in stoichiometry and mole calculations
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Chemistry students, educators, and anyone involved in chemical calculations or stoichiometry who seeks to clarify the relationship between gram formula weight and moles.

erisedk
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Homework Statement


How many moles is 0.01 gram formula weight of NaCN?

Homework Equations

The Attempt at a Solution


I thought it meant 0.01/49 moles of NaCN.
The solution simply says 0.01 moles. Why?
 
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erisedk said:

Homework Statement


How many moles is 0.01 gram formula weight of NaCN?

Homework Equations

The Attempt at a Solution


I thought it meant 0.01/49 moles of NaCN.
The solution simply says 0.01 moles. Why?
What's the definition of 1 mole of a particular substance? How is it calculated?
 
erisedk said:
gram formula weight

An obscure and rarely used term in my experience, but definitely not equivalent to just gram.
 

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