Calculating Moment of Force Produced at Point A

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SUMMARY

The discussion centers on calculating the moment of force produced at point A when a force of 200 lb is applied to a cable to raise a lamp post. The moment is calculated using the formula MA = Fd, resulting in 1035.3 ft-lb. The user initially misinterprets the angle between the moment arm and the force, mistakenly using the cosine of 75 degrees instead of correctly identifying the perpendicular component of the moment arm. Clarification on the angles involved is necessary for accurate calculations.

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  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with force components and their relationship to moment arms
  • Basic principles of static equilibrium in physics
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musicmar
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Homework Statement


In order to raise the lamp post from the position shown, force F is applied to the cable. If F = 200 lb, determine the moment produced by F about point A. I've attached the diagram. I apologize for the terrible quality. The length of the post from A to B is 20 ft.


The Attempt at a Solution



MA=Fd
=200 lb (cos 75) (20 ft) = 1035.3 ft-lb

I think I somehow reasoned that the angle between AB and AC is 15°, so its complement is 75°. I said that the component of the force acting perpendicular to the moment arm is 200 cos 75. I know this is backwards from what it is supposed to be. It should be the force times the perpendicular component of the moment arm. I'm not sure that it matters much here, but I don't know how to describe the perpendicular moment arm.


Thank you.
 

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musicmar said:
I think I somehow reasoned that the angle between AB and AC is 15°, so its complement is 75°.

Total angle is 180 degree not 90 degree
 
I meant between F and an imaginary line perpendicular to the post at B, so the angle there would be 75 degrees. I don't think that's where my mistake is. If anything, it's what these angles mean.
 
Last edited:

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