Calculating Moment of Inertia for a Thin Spherical Shell

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SUMMARY

The discussion centers on calculating the moment of inertia for a rubber ball modeled as a thin spherical shell. The correct formula for the moment of inertia of a thin spherical shell is I = (2/3)Mr², where M is mass and r is radius. The user initially applied the formula for a solid sphere, resulting in incorrect calculations. The correct moment of inertia for the given parameters is approximately 1.17 x 10^-4 kg*m².

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tak08810
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Ok this problem is really really ticking me off because it seems so damn simple.

"A rubber ball has a mass of 60.0 g and a diameter of 6.98 cm. Find the moment of inertia about its diameter. Model the ball as a thin spherical shell."

Ok so moment of interia for a sphere shaped object is 2/5Mr^2 correct? So I convert grams to kg, cm to meters, plug the numbers in (radius = 0.0349 m) and get 2.92 *10^-5 kg*m^2. But this is wrong? I don't understand what I'm doing wrong. I assume I'm looking at this problem in completely the wrong way. Here is the list of attempts I've put in:

Submission # Try Submitted Answer
1 Incorrect. (Try 1) 2.92 *10^-5 kg*m^2
2 Incorrect. (Try 2) 1.17 *10^-4 kg*m^2
3 Incorrect. (Try 3) 7.30 *10^-5 kg*m^2
4 Incorrect. (Try 4) 2.92 *10^-4 kg*m^2
5 Incorrect. (Try 5) 2.93 *10^-5 kg*m^2
6 Incorrect. (Try 6) 2.91 *10^-5 kg*m^2
7 Submission not graded. Use more digits. 2.9 *10^-5 kg*m^2
8 Submission not graded. Use fewer digits. 1.1692896 *10^-4 kg*m^2
9 Incorrect. (Try 7) 1.1692 *10^-4 kg*m^2
10 Incorrect. (Try 8) 0.000 kg*m^2
11 Incorrect. (Try 9) 0.000292 kg*m^2
12 Incorrect. (Try 10) 0.000117 kg*m^2
13 Incorrect. (Try 11) 0.0004188 kg*m^2
14 Incorrect. (Try 12) 0.004188 kg*m^2
15 Incorrect. (Try 13) 0.000251 kg*m^2
16 Incorrect. (Try 14) 0.000251 g*m^2
17 Incorrect. (Try 15) 2.92 *10^-5 kg*m^2
 
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NVM I got the answer from another site. Thanks anyways!
 

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