There is a steamroller with total mass 12000 kg on a 4° slope. It has 2 wheels (full homogeneous cylinders) with mass 3000 kg (each one 3000 kg) and diameter 1,2 m (radius 0,6 m). How big would the acceleration of the steamroller be if brakes got broken.
Result: 0.56 m/s^2
(J-moment of inertia, M-torque, α-angular acceleration)
The Attempt at a Solution
i assumed that the gravity forces of steamroller on the axis of wheels is equal (half-half). I tried to write torques on one of the wheels. 12000 kg (whole steamroller) - 3000 kg (wheel1) - 3000 kg(wheel2) = 6000 kg (driver, cabin, engine ....) --> 3000 kg on each wheel[/B]