Calculating Momentum: Can Anyone Help?

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To calculate the momentum change of a 220g ball that falls and rebounds, the initial momentum (downward) is negative, while the final momentum (upward) is positive. The correct formula for momentum is p=mv, where mass should be in kilograms, leading to an initial momentum of -0.528 kg·m/s and a final momentum of 0.396 kg·m/s. The change in momentum is found by subtracting the initial momentum from the final momentum, resulting in a total change of 0.924 kg·m/s. It's important to ensure consistent units when performing these calculations. Understanding the vector nature of momentum is crucial for accurately determining the changes.
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Can anyone help with this ?
A 220g ball falls vertically downward, hitting the floor with a speed of 2.4 m/s and rebounding upward with a speed of 1.8 m/s.
A.) Find the magnitude of the change of the balls momentum (up=positive)
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396

B.) Find the change in the magnitude of the balls momentum. (Neg. value=decrease in magnitude)

Can anyone help on this 2 parts?
 
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i guess its right the way you have done it...
 
Huskies213 said:
Can anyone help with this ?
A 220g ball falls vertically downward, hitting the floor with a speed of 2.4 m/s and rebounding upward with a speed of 1.8 m/s.
A.) Find the magnitude of the change of the balls momentum (up=positive)
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396

B.) Find the change in the magnitude of the balls momentum. (Neg. value=decrease in magnitude)

Can anyone help on this 2 parts?

I'm not sure what the difference between a and b is supposed to be...

Anyway, \mathbf{\Delta p} = \mathbf{p_f} - \mathbf{p_i}. Remember that these are vectors, so in your coordinate system, the initial p is negative, your final p is positive.

Note:
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396
Watch the units! Your first calculation is good, but your second is wrong since you are using g, not kg.

-Dan
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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