Calculating Momentum: Can Anyone Help?

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The discussion focuses on calculating the momentum change of a 220g ball that falls and rebounds. The initial momentum is calculated using the formula p=mv, where the mass is converted to kilograms (0.22 kg) and the rebound speed is 1.8 m/s, resulting in a final momentum of 0.396 kg·m/s. The change in momentum is determined by the vector difference between the final and initial momentum, with the initial momentum being negative due to the downward direction. Participants emphasize the importance of using consistent units, specifically kilograms instead of grams.

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Can anyone help with this ?
A 220g ball falls vertically downward, hitting the floor with a speed of 2.4 m/s and rebounding upward with a speed of 1.8 m/s.
A.) Find the magnitude of the change of the balls momentum (up=positive)
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396

B.) Find the change in the magnitude of the balls momentum. (Neg. value=decrease in magnitude)

Can anyone help on this 2 parts?
 
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i guess its right the way you have done it...
 
Huskies213 said:
Can anyone help with this ?
A 220g ball falls vertically downward, hitting the floor with a speed of 2.4 m/s and rebounding upward with a speed of 1.8 m/s.
A.) Find the magnitude of the change of the balls momentum (up=positive)
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396

B.) Find the change in the magnitude of the balls momentum. (Neg. value=decrease in magnitude)

Can anyone help on this 2 parts?

I'm not sure what the difference between a and b is supposed to be...

Anyway, [tex]\mathbf{\Delta p} = \mathbf{p_f} - \mathbf{p_i}[/tex]. Remember that these are vectors, so in your coordinate system, the initial p is negative, your final p is positive.

Note:
i used p=mv; (.22kg)(1.8) = .396 as well as (220g)(1.8)=396
Watch the units! Your first calculation is good, but your second is wrong since you are using g, not kg.

-Dan
 

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