Calculating Motion with Constant Acceleration: Solving for Time and Distance

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A body moving with constant acceleration covers 60.0m in 5.0s, reaching a final velocity of 15.0m/s. The calculated acceleration is 1.2 m/s² and the initial velocity is 9.0 m/s. To determine how long it had been in motion before reaching the first point, the final velocity is considered as the initial velocity from part A, with constant acceleration applied. The discussion highlights the confusion regarding the initial velocity, with the conclusion that it should be considered as 0.0 m/s for the time calculation. This clarification helps in solving for the time and distance from the starting point when passing the second point.
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Homework Statement



A body moving with constant acceleration in a straight line covers the distance between two points 60.0m apart in 5.0s. Its velocity as it passes the second point is 15.0m/s.

a) What is:
i) The acceleration of the object?
ii) Its initial velocity?

b) Assuming constant acceleration how long had it been in motion before it reached the first point?

c) How far is it from the starting point when it passes the second of the two points which are 60.0m apart?



Homework Equations



constant acceleration equations


The Attempt at a Solution




I have solved part a) where the acceleration = 1.2 m/s^2 and the initial velocity = 9.0m/s

Now I am having trouble with part B. (which is making part C tricky)

What I understand is that for part B the final velocity would be the the initial velocity from part A (after drawing a sketch) and the acceleration is constant. So I have two known quantities:

V(final) = 9.0 m/s
a = 1.2 m/s^2

I am missing a quantity to be able to solve for time, but where am I missing it?

The only thing I can think of is that is the initial velocity is 0.0 m/s , but I'm not sure this is logical.

Any idea?
Thanks!
 
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Yes, zero initial velocity. It says, "how long had it been in motion", which implies we are timing from the time it started moving.
 
Fantastic! Thank you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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