Calculating Motion with Constant Acceleration: Solving for Time and Distance

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SUMMARY

The discussion focuses on calculating motion with constant acceleration, specifically solving for acceleration, initial velocity, time, and distance. The acceleration of the object is determined to be 1.2 m/s², and the initial velocity is found to be 9.0 m/s. The forum participants clarify that for calculating the time before reaching the first point, the initial velocity should be considered as 0.0 m/s, allowing for the correct application of kinematic equations. This understanding is crucial for accurately determining the time and distance traveled.

PREREQUISITES
  • Understanding of kinematic equations for constant acceleration
  • Familiarity with basic physics concepts such as velocity and acceleration
  • Ability to manipulate algebraic equations
  • Knowledge of motion in one dimension
NEXT STEPS
  • Study the kinematic equation: \(d = v_i t + \frac{1}{2} a t^2\)
  • Learn how to derive time from the equation \(v_f = v_i + at\)
  • Explore graphical representations of motion with constant acceleration
  • Investigate real-world applications of constant acceleration in physics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion under constant acceleration, particularly in solving related problems in kinematics.

cal.queen92
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Homework Statement



A body moving with constant acceleration in a straight line covers the distance between two points 60.0m apart in 5.0s. Its velocity as it passes the second point is 15.0m/s.

a) What is:
i) The acceleration of the object?
ii) Its initial velocity?

b) Assuming constant acceleration how long had it been in motion before it reached the first point?

c) How far is it from the starting point when it passes the second of the two points which are 60.0m apart?



Homework Equations



constant acceleration equations


The Attempt at a Solution




I have solved part a) where the acceleration = 1.2 m/s^2 and the initial velocity = 9.0m/s

Now I am having trouble with part B. (which is making part C tricky)

What I understand is that for part B the final velocity would be the the initial velocity from part A (after drawing a sketch) and the acceleration is constant. So I have two known quantities:

V(final) = 9.0 m/s
a = 1.2 m/s^2

I am missing a quantity to be able to solve for time, but where am I missing it?

The only thing I can think of is that is the initial velocity is 0.0 m/s , but I'm not sure this is logical.

Any idea?
Thanks!
 
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Yes, zero initial velocity. It says, "how long had it been in motion", which implies we are timing from the time it started moving.
 
Fantastic! Thank you.
 

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