Calculating Oxygen Cylinder Usage at 2.4 L/min

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To calculate the duration of an oxygen cylinder at a flow rate of 2.4 L/min, the Ideal Gas Law (PV=nRT) can be applied. The cylinder has a gauge pressure of 2500 kPa and a volume of 10 liters, and the flow rate is measured at atmospheric pressure. Atmospheric pressure is approximately 101.3 kPa, which is essential for determining the volume of gas available at that pressure. By calculating the total liters available at 2500 kPa and dividing by the flow rate, the time the cylinder will last can be determined. The discussion highlights different approaches to solving the problem, emphasizing personal preference in calculation methods.
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A standard cylinder of oxygen used in a hospital has the following characteristics at room temperature (300 K): gauge pressure = 2500 kPa, volume = 10 liters. How long will the cylinder last if the flow rate, measured at atmospheric pressure, is constant at 2.4 liters/min?

I'm lost on this one...how do I relate flow rate to the Ideal Gas Law?
 
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PV= nRT so that Volume is inversely propotional to pressure. What is "atmospheric pressure" in terms of kPa and what would the volume be at that pressure?
 
If the flow rate is 2.4L/min, how many moles per minute is that? Remember, it is 2.4 L at 1atm and 300 K every minute. You can use the ideal gas law to find the total # of moles of gas in the tank to begin with. You can probably figure it out from there.
 
I don't see why you would need to calculate moles. You are given volume (at 2500 kPa) and that at atmospheric pressure, 2.4 liters/min come out. Use PV= nRT (where nRT is constant) to determine the number of liters at atmospheric pressure and divide by 2.4 liters/min.
 
That's true. It's more logically straightfoward to me to calculate the actual amount of stuff coming out of the tank and compare that to the total amount of stuff in the tank, but your method involves less calculation. It's a matter of personal preference I guess.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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