Calculating PD between +q and -q Charges at Points A & B

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Homework Help Overview

The discussion revolves around calculating the potential difference between two point charges, +q and -q, located at points A and B, respectively, separated by a distance R. Participants are exploring methods to compute this potential difference using integration of the electric field and direct potential calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the potential difference using two methods: integrating the electric field and directly finding the potentials at points A and B. They express confusion regarding their results, which yield an undefined value.
  • Some participants question the limits of integration and the necessity of integration given the presence of only two charges.
  • Others suggest that the contributions from the two charges may cancel each other out, leading to unexpected results.

Discussion Status

Contextual Notes

Participants are navigating potential misunderstandings about the integration process and the assumptions regarding the electric field created by two point charges. The original poster's calculations appear to be complicated by the undefined results they are encountering.

Highwaydude
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Homework Statement



Charges +q and -q at points A and B respectively separated by distance R. Required to calculate the potential difference between these 2 points.

Homework Equations



I want to do in two ways.. i.e once by integrating the electric field and the other by directly finding the potential at the two points and then subtract them to have the difference

The Attempt at a Solution


Both of my trials have yielded a 2kq/0 which is a bit absurd...
I do like this>
Vb -Va= - ((integration sign)kq/r^2 dr-(int.sign)kq/(R-r)^2 dr)
between the limits 0 to R.. It yields 2kq/0(wth!)-2kq/R...
So yeah.. I need help. Oh and K = 1/4pi e0
 
Last edited:
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please check if you are putting the limit right
 
also i don't knw why r u integrating when only two charges are present
 
i am calculating the net electring field... i guess the two kq/0's cancel out one being negative, but its just not coming. i mean bot hare coming out to be positive...
 
Heres the working... sorry, i can't find my mobile phone data cable.. had to do it in paint... http://hostmypicture.com/images/untitlete.png
 
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