- #1

Paul Uszak

- 84

- 7

For three dice, you can have 6 * 6 * 6 = 216 permutations (order matters). The dice has a uniform probability distribution of p(x) = 1/6. Easy.

I'm trying to get an estimate of how many permutations you can have if a variable has a normal probability distribution. So for example, if a variable has mean 100, standard deviation 5, how many permutations can I get if I measure the variable 3 times repeatedly? I suspect that someone's somehow going to include a %age in their answer...

I'm trying to get an estimate of how many permutations you can have if a variable has a normal probability distribution. So for example, if a variable has mean 100, standard deviation 5, how many permutations can I get if I measure the variable 3 times repeatedly? I suspect that someone's somehow going to include a %age in their answer...

Last edited: