Calculating pH of Water After Adding HCl and NaOH

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Adding 1M HCl and 1M NaOH to pure water results in a neutralization reaction that produces water and NaCl. The net effect is that the solution remains neutral, leading to a pH of 7. However, the actual pH may vary depending on the ionic strength of the solution, which is an advanced consideration. The basic logic of the reaction is correct, but the final pH can be influenced by factors not accounted for in a simple calculation. Understanding these nuances is essential for accurate pH determination in practical scenarios.
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Homework Statement


What will the pH be by adding 1M HCL and 1M NaOH to pure water?

Homework Equations


pH= -log[H+]

The Attempt at a Solution


Well, If we form the reaction formula we get
HCl + NaOH ---> H20 + NaCl

This is a neutralizing reaction, so the net effect produces just water. Therefore the pH doesn't change. Is this logic right?
 
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Correct.
 
Depends on whether you are expected to take ionic strength of the solution into effect, or not. That's typically at least undergraduate level though.
 
And don't forget the question was: what is the pH?
 

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