Calculating Point Charge Potential at (0,0,0)

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SUMMARY

The discussion focuses on calculating the electrostatic potential of a point charge at the origin (0,0,0), represented by the equation \(\phi = \frac{1}{r}\). The gradient of the potential is derived as \(\nabla\phi = -\frac{\vec{r}}{r^3}\), leading to the conclusion that \(\Delta\phi = 0\) outside the origin. However, at the origin, the potential diverges, and the Dirac delta function emerges as the charge density for a point particle, confirmed through the divergence theorem and limit processes.

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Yegor
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Hallo!

Homework Statement


Consider electrostatic Potential of point charge at point (0,0,0)
[tex]\phi = 1/r[/tex]
I'm trying to calculate [tex]\Delta\phi[/tex]

Homework Equations



The Attempt at a Solution


Actually it's not a difficult problem outside (0,0,0):

[tex]\nabla\phi = -\frac{\vec r}{r^3}[/tex]
[tex]\Delta\phi = 0[/tex]

But i also know, that i should become Dirac-Delta function (charge density for point particle). What is the problem in point (0,0,0)?
I understand that Potential goes there to infinity, but how can i work it out mathematically?
 
Last edited:
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Using the integral definition of div, it can be shown that
div(r(vec)/r^3)=4pi delta(r).
This can also be shown by appying the div theorem and taking the limit as r-->0.
What book are you using? Graduate texts do this.
 

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