Calculating Pool Depth: An Angle of 14o

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SUMMARY

The discussion focuses on calculating the depth of a pool based on the angle of light refraction. The pool is 5.50 meters wide, and a ray of light exits at an angle of 14 degrees. Using Snell's Law, the angle of refraction is determined to be 10.48 degrees, leading to a calculated depth of 1.01 meters. The correct approach involves using the complementary angle (90 - 14 degrees) for the angle of refraction in the calculations.

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Homework Statement


There is a pool 5.50 meter wide filled to the top with water, A ray of light originates at the
bottom left corner of the pool leaves the far upper right side at an angle of 14o. The question is asking for the depth of the pool



Homework Equations



n1sintheta=n2sintheta

The Attempt at a Solution



1sin14=1.33sintheta
tetha = 10.48 degree
using Tan the depth comes to 1.01m

My question is do i use 14 for the angle or do I have to do 90-14, and if yes why?
 

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You have to use (90 - 14) which is the angle of refraction.
 

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