Calculating Pool Depth: An Angle of 14o

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Homework Statement


There is a pool 5.50 meter wide filled to the top with water, A ray of light originates at the
bottom left corner of the pool leaves the far upper right side at an angle of 14o. The question is asking for the depth of the pool



Homework Equations



n1sintheta=n2sintheta

The Attempt at a Solution



1sin14=1.33sintheta
tetha = 10.48 degree
using Tan the depth comes to 1.01m

My question is do i use 14 for the angle or do I have to do 90-14, and if yes why?
 

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You have to use (90 - 14) which is the angle of refraction.