Calculating Pool Depth with 48 Degrees Depression Angle

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SUMMARY

The discussion focuses on calculating the visible depth of a swimming pool when viewed at a depression angle of 48 degrees. Given that the pool's actual depth is 2.6 meters, the observer's perception of depth is influenced by the angle of view. The problem highlights the optical illusion created by varying depression angles, which can lead to misconceptions about the pool's true depth. The discussion emphasizes the importance of understanding geometric principles in visual perception.

PREREQUISITES
  • Basic understanding of geometry and angles
  • Knowledge of trigonometric functions, specifically tangent
  • Familiarity with optical illusions and perception
  • Ability to interpret diagrams and visual aids
NEXT STEPS
  • Research trigonometric calculations involving angles and depth perception
  • Study the principles of optical illusions in physics
  • Explore geometric visualization techniques for better understanding
  • Learn about the effects of viewing angles on perception in various contexts
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Students studying physics, educators teaching geometry, and anyone interested in the principles of visual perception and optical illusions.

arvin305
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An observator is looking at a coin that is located on a swimming pool's floor with a depression Angle of 48 degrees. Knowing that the swimming pool's depth is 2.6 metres, calculate the depth that the observator can see.

(Usually when you look at a swimming pool from with a smaller depression angle, you have the impression that the swimming pool isn't deep even though it is, that is the situation in this problem)

P.S. I study in a french school in Quebec, if you don't understand something i said please tell me.

Here is an image that I made to help myself understand the problem

http://img503.imageshack.us/img503/340/physics7qo.jpg
 
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Oh , yeah the diagram i drew can be wrong... As i said i made it myself to understand this question.
 

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