- #1

Const@ntine

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## Homework Statement

A non-transclucent container in the form of a cylinder, has a diameter of 3.00 m, has its top part open, and is filled with water. When the sun created a 28.0 degree angle with the horizontal, the light doesn't illuminate the bottom of the container. What's the depth of the container?

## Homework Equations

n

_{1}*sinθ

_{1}= n

_{2}*sinθ

_{2}

## The Attempt at a Solution

First things first, the 28.0 degree angle is the one with the horizontal, so the angle of prolapse, is going to be 62.0 degrees (angle between the vertical and the ray of light).

Then, what I did was take the known formula, and with the given Refractive Indexes (n

_{water}= 1.333 & n

_{air}= 1.0002293). I ended up with the refraactive angle being 41.5 degrees. And then I got stuck.

I thought about tying it in with the speed of light, and finding the hypotenouse of the hypothetical triangle, but I don't know the time. I tried to figure out how to use the diameter but I can't come up with anything.

Then, I figured that I could take an unorthodox route, and imagine the container as being empty. In that case, the light reaches the bottom of the container, and with a few calculations I'll find the depth. Turns out the number comes out wrong.

So, any tips? Any kind of help is appreciated!

PS: The answer according to the book is 3.39 m.