Calculating Potential Energy in a Parallel Plate Capacitor

[xswtxoj]

#8

Homework Statement

A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the separation between the plates is d= 0.0242m, what's the potential energy?

Homework Equations

v=w/q

The Attempt at a Solution

not sure, where to begin but...
V= w/q
w=1/2cv sq
F= keqq/r
F= 8.99e9 (6.62e-6)/.0242 sq

 

[LowlyPion]

I think you'll need to draw a picture here.

 

[xswtxoj]

i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle

 

[LowlyPion]

i have 2 parallel lines then the distance btw the lines is d= .0242, then a pendulum ball @ an angle

What's the length of the pendulum?

 

[xswtxoj]

there isn't it only tells u the angle and the distances btw the 2 parallel lines