Calculating Power Dissipation in a Simple Circuit

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Homework Statement


Smiling young woman with long curly light-brown hair, wearing a purple and white newsboy cap, a yellow-green jacket, and red and white beaded necklaces, in front of palm trees and a building.


How much power is dissipated by R1? (R1=8 Ω, R2=17 Ω, V=6 V.)

Sorry the picture is so big!

Homework Equations





The Attempt at a Solution



P = E^2/R = 8^2/6 = 10.67W what am I doing wrong?
 
No P=IV so the change in power is the dissipation of power so delta P=IV-IV
so use v=IR and get P=I^2R -I^2R for the points after and at (before) the resistor, also remember always final-initial
 
So I would do...
I = E/Req = 6/25
P = 0.24^2 * 8 - 0.24^2 * 17 = -0.5184
Negative? Why would it be negative?
 
Can someone explain this...

No P=IV so the change in power is the dissipation of power so delta P=IV-IV
so use v=IR and get P=I^2R -I^2R for the points after and at (before) the resistor, also remember always final-initial

I don't understand what Vi and Vf are?
 
so i need to multiply the voltage drop across the resistors by the current. but how do i calculate the voltage drop?