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## Homework Statement

What power is dissipated by the R2=3.0Ω resistor in the figure if R1=6.0Ω?

Battery 1: 12 V

Battery 2: 15 V

Resistor 1: 3.0 Ω

Resistor 2: 6.0 Ω

## Homework Equations

P = V

^{2}/R

R

_{total}= R

_{1}+ R

_{2}

## The Attempt at a Solution

I started on the left side and used the formula, P = V

^{2}/R. I plugged 12 in for V and 3 for R. That resulted in 24 W from the battery on the left. I used the same formula on the right side but plugged in 15 for V and 3 for R. That resulted in 75 W. I added the 2 together and got 99 W.

That was the wrong answer.

I also tried adding 12 and 15 together for V and dividing it by the same R, 3. That gave me 240 W which was also an incorrect answer.

I tried to ratio it as well by taking the left side and 12

^{2}/9 then taking that result and dividing it by 3. I then did essentially the same to the other side but with 15 for the V and then taking a ratio of that as well. That resulted in 80 W. Once again, the answer was incorrect.

Am I even using the right equation?