Calculating Power Dissipation in Series Lightbulb Circuit

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SUMMARY

The discussion centers on calculating power dissipation in a series circuit with two 97 W lightbulbs connected to a 114 V supply. The user incorrectly calculated the total resistance as 228 ohms, leading to a current of 0.5 A and a power dissipation of 57 W per bulb. The correct approach requires recognizing that in a series circuit, the total resistance is the sum of individual resistances, and the power dissipated by each bulb must be recalculated using the correct current derived from the actual resistance values.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Knowledge of series circuit characteristics
  • Familiarity with power calculations (P = VI)
  • Basic electrical resistance concepts
NEXT STEPS
  • Review series circuit calculations and resistance summation
  • Learn about power dissipation in electrical components
  • Study the implications of voltage drops across series components
  • Explore practical applications of Ohm's Law in circuit design
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Students in electrical engineering, educators teaching circuit theory, and hobbyists working on basic electronics projects.

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Power...Did I do this right??

Homework Statement


Two 97 W (114 V) lightbulbs are wired in series, then the combination is connected to a 114 V supply. How much power is dissipated by each bulb?


Homework Equations


P = VI
I = E/Req

The Attempt at a Solution


I = 114/228 =0.5
P = 0.5 * 114 = 57
Is this right?
 
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Oh my gosh its wrong! Why am I not getting these Power problems right! I thought that was the equation...
 
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