Calculating Pressure at High Altitudes Using Air Density and Temperature

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SUMMARY

This discussion focuses on calculating atmospheric pressure at an altitude of 11,000 m, where the air temperature is -56.5 °C and the air density is 0.364 kg/m³. The primary method discussed involves using the equation ρ = p M / R T to derive pressure, alongside the differential equation dp / dy = -ρ g. The user seeks clarification on integrating these equations and acknowledges the need for the molar mass of air at that altitude to complete the calculations. A reference to the Barometric formula is also provided for further comparison.

PREREQUISITES
  • Understanding of the Ideal Gas Law (ρ = p M / R T)
  • Familiarity with differential equations in fluid dynamics
  • Knowledge of atmospheric pressure concepts
  • Basic understanding of integration techniques
NEXT STEPS
  • Research the Barometric formula for atmospheric pressure calculations
  • Learn about the molar mass of air and its variation with altitude
  • Study integration techniques for solving differential equations
  • Explore the relationship between air density, temperature, and pressure in atmospheric science
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Students in physics or engineering, meteorologists, and anyone interested in atmospheric pressure calculations at high altitudes.

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Homework Statement



At an altitude of 11,000 m, the air temperature is -56.5 °C and the air desity is 0.364 kg / m3. What is the pressure of the atmosphere at that altitude?

Homework Equations



no equations found

The Attempt at a Solution



Ok. The problem gives the air density and using the expression ρ = p M / R T we can easily find the pressure. But suppose I want to find it by using the expression dp / dy = -ρ g, with ρ = p M / R T. In this case I would need to integrate both dy and dT. Am I right? And how could I do this? I've tried working on one attempt but it did'nt work. Maybe the reason is that I did'nt know the molar mass of the air in that altitude? (sorry my bad english). My work is shown below.

dp / dy = -ρ g
ρ = p M / R dT

dp = - (dy p M g / R dT)

- ∫dy M g = R ∫dT (∫dp / P)

Ln P1 / P0 = - (Δy M g) / ΔT

Finally,

P1 = P0 e - (Δy M g / R ΔT)
 
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kent davidge said:

Homework Statement



At an altitude of 11,000 m, the air temperature is -56.5 °C and the air desity is 0.364 kg / m3. What is the pressure of the atmosphere at that altitude?

Homework Equations



no equations found

The Attempt at a Solution



Ok. The problem gives the air density and using the expression ρ = p M / R T we can easily find the pressure. But suppose I want to find it by using the expression dp / dy = -ρ g, with ρ = p M / R T. In this case I would need to integrate both dy and dT. Am I right? And how could I do this? I've tried working on one attempt but it did'nt work. Maybe the reason is that I did'nt know the molar mass of the air in that altitude? (sorry my bad english). My work is shown below.

dp / dy = -ρ g
ρ = p M / R dT

dp = - (dy p M g / R dT)

- ∫dy M g = R ∫dT (∫dp / P)

Ln P1 / P0 = - (Δy M g) / ΔT

Finally,

P1 = P0 e - (Δy M g / R ΔT)
You might want to compare your model of the Earth's atmosphere with this one:

https://en.wikipedia.org/wiki/Barometric_formula
 
Oh thanks. It was useful to me.
 

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