Calculating Probabilities with Binomial Distribution

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Discussion Overview

The discussion revolves around calculating probabilities using the binomial distribution, specifically for scenarios where the probability of an event occurring is 0.6 and the total number of trials is 5. Participants seek clarification and assistance in solving specific probability problems related to this distribution.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant asks for help calculating the probability of 1 and 4 events occurring out of 5 trials, given a probability of 0.6.
  • Several participants suggest using the binomial distribution formula, f(k)=\left( \begin{array}{c} n \\ k \end{array} \right) p^k (1-p)^{n-k}, to find the probabilities.
  • One participant expresses confusion about their calculations and requests a solution to be shown step-by-step.
  • Another participant points out that the arithmetic might be where the confusion lies and encourages using the formula with the correct values.
  • A later reply acknowledges a mistake with decimals and confirms understanding after receiving initial guidance, while still inquiring about alternative methods to solve the problem.

Areas of Agreement / Disagreement

Participants generally agree on the use of the binomial distribution formula for solving the problem. However, there is no consensus on alternative methods, and some participants express uncertainty about their calculations.

Contextual Notes

Some participants mention difficulties with arithmetic and decimal placement, which may affect their ability to arrive at the correct answers. The discussion does not resolve these issues, leaving the potential for misunderstanding in calculations.

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Hi,Can anyone help me with this one?

Probability of an event occurring is 0.6

Find,
1)Probability of 1 of such events occurring out of total 5?

2)and 4 of such event occurring out of total 5.?



Answers given are:

1) 0.768
2) 0.2592


Please help me out by giving and explaining this one?..
thnks in advance
 
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You may want to use the binomial distribution [tex]f(k)=\left( \begin{array}{c} n \\ k \end{array} \right) p^k (1-p)^{n-k}[/tex], where n is the number of trials, and k the number of times an event whose probability is 0.6 occurred.
 
radou said:
You may want to use the binomial distribution [tex]f(k)=\left( \begin{array}{c} n \\ k \end{array} \right) p^k (1-p)^{n-k}[/tex], where n is the number of trials, and k the number of times an event whose probability is 0.6 occurred.


I tried..but still not getting the ans..dunno where am going wrong..could u pls solve it and show me...
thnk u very much!...i guess i am making the same mistake again n again..but can't see thro ' it..will really appreciate if u solve it and explain...

U r right tht we have to use binomial distribution..is there any other way also to solve it?

thnks
 
Complete words, please!

RSS said:
I tried..but still not getting the ans..dunno where am going wrong..could u pls solve it and show me...
thnk u very much!...i guess i am making the same mistake again n again..but can't see thro ' it..will really appreciate if u solve it and explain...

U r right tht we have to use binomial distribution..is there any other way also to solve it?

I'm not sure at all where you're going wrong. You have the formula -- just plug in the appropriate values and you have the answer. What are you getting, and how?
 
You have already been told to use
[tex]f(k)=\left( \begin{array}{c} n \\ k \end{array} \right) p^k (1-p)^{n-k}[/tex]

When p= 0.6, n= 5, P(1)= [itex]\frac{5!}{(4!)(1!)}.6^1 .4^4[/itex]
[itex]= 5(.6)(0.025)= 0.0768[/itex]. Was it the arithmetic you had trouble with?

To answer (2) take k= 4 rather than 1.
 
sorry frnds..was making a very silly mistake with decimals..I got it after radou's 1st reply..was just trying to work out if there is any other way to solve besides using the binomial formula..
anyways, i have stuck with wht u all suggest..thnks again all of you!..appreciate it!:smile:
 

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