Calculating Projectile Trajectory Without Air Resistance

Click For Summary
SUMMARY

The discussion focuses on calculating the trajectory of a projectile, specifically a cannonball, when fired at a speed of 1440 ft/s on level ground without air resistance. The key formula for determining the range of the projectile is derived from basic physics principles, specifically the equations of motion. The user is directed to resources such as HyperPhysics for further understanding of parabolic motion and trajectory calculations. The discussion emphasizes the importance of understanding the trajectory formula to accurately predict where the projectile will land.

PREREQUISITES
  • Basic understanding of quadratic equations
  • Familiarity with projectile motion concepts
  • Knowledge of the formula for calculating range in projectile motion
  • Ability to perform basic algebraic calculations
NEXT STEPS
  • Research the formula for projectile motion range: R = (v^2 * sin(2θ)) / g
  • Learn how to calculate the angle of projection for maximum range
  • Explore the effects of air resistance on projectile motion
  • Study the differences between two-dimensional and three-dimensional projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the fundamentals of trajectory calculations in a vacuum.

stamter3
Messages
2
Reaction score
0
Greetings,

Before I begin my problem, I would like to confess that I understand almost nothing about physics. My math is limited to what I am doing in class right now as a ninth grader ( I understand quadratics...). I am doing a research project, and I need some help.

Homework Statement



What I am looking for is the trajectory formula when firing a cannon with no air resistance. For example, If I fired a cannon on level ground, and fire a round at 1440 ft/s, where will my round land if it does not encounter any obstacles.


Homework Equations



Please show me a formula I can use for this, and where i plug in the numbers.

Thanks in advance.
 
Physics news on Phys.org
Thanks its perfect!
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
6
Views
2K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K