Calculating Properties of Helium Gas Under Isothermal Compression

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To calculate the properties of a 2.00 mol sample of helium gas undergoing isothermal compression from 0.400 atm to 1.20 atm at 300K, the ideal gas law (PV=nRT) is essential. The volume of the gas can be determined using this formula, while the work done on the gas during compression is related to the natural logarithm of the volume change. In isothermal processes, the internal energy remains constant, meaning the work done on the gas equals the heat transferred out of the gas. Understanding the relationship between pressure, volume, and temperature is crucial for solving these types of problems. This approach will yield the necessary calculations for volume, work, and heat transfer.
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a 2.00 mol sample of helium gas at 300K and 0.400atm pressure is compressed isothermally to 1.20atm
Find the volume of the gas, work done on the gas and the energy transferred by heat

just wondering how to approach this question, and what formulae i hould use where?
 
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The formula to use is the one most obvious formula: the ideal gas law formula. It has three variation, called Charles' Law, Boyle' Law and Gaye-Lusac's Law, but I recommend sticking with the ideal gas formula. (Starts with "PV," remember?)

In an isothermal compression, the temperature stays the same, so there is no change in internal energy, therfore, the work on the gas must equal the heat given off by the gas.

Since ideal isothermal processes are hyperbolic, the work done must be a "natural log" function of the change in volume. You have probably seen only one natural log function so far, am I right?
 
thankyou for your help
 

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