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Chem10

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- I am attempting to calculate the proportional luminosity of a fictitious star using surface area and kelvin

To what level of accuracy can I expect from the formula L ∝ AT^4?

Where L = Luminosity, A = surface area and T = Temperature

L ∝ AT^4

L ∝ 4π · (r)^2 · (T)^4

If I replace r and T with the proportional increase/decrease in comparison to the Sun I should get the proportional increase in luminosity.

I would be very grateful if someone would be able to confirm my calculations.

I am attempting to calculate the proportional luminosity of a fictitious star using surface area and temperature in kelvin.

To what level of accuracy can I expect from the formula L ∝ AT^4?

Where L = Luminosity, A = surface area and T = Temperature

L ∝ AT^4

L ∝ 4π · (r)^2 · (T)^4

If I replace r and T with the proportional increase/decrease in radius and temperature in comparison to the Sun, I should get the proportional increase/ decrease in proportional luminosity.

If the value is less than 1* then it is this value times less luminous than the Sun and if the value is more than 1* then it is this value times more luminous than the Sun.

I would be very grateful if someone would be able to confirm my calculations and above statements to ensure I've understood correctly.

Thank you again for your time and help.

*(edited from "0"s to "1"s) highlight above by *)

To what level of accuracy can I expect from the formula L ∝ AT^4?

Where L = Luminosity, A = surface area and T = Temperature

L ∝ AT^4

L ∝ 4π · (r)^2 · (T)^4

If I replace r and T with the proportional increase/decrease in radius and temperature in comparison to the Sun, I should get the proportional increase/ decrease in proportional luminosity.

If the value is less than 1* then it is this value times less luminous than the Sun and if the value is more than 1* then it is this value times more luminous than the Sun.

I would be very grateful if someone would be able to confirm my calculations and above statements to ensure I've understood correctly.

Thank you again for your time and help.

*(edited from "0"s to "1"s) highlight above by *)

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